|
Re: vsize function [message #336 is a reply to message #331] |
Wed, 06 February 2002 04:11 |
Mike
Messages: 417 Registered: September 1998
|
Senior Member |
|
|
It is the number of bytes used to store your number. It is stored under the format 3.84838 * 10^5. One byte is used for the exponent and 3 for the number.
With larger numbers it can happen, like VSIZE(10000000)=2, that the result is smaller because it will only store the exponent which always uses 1 byte and the number, 1 in this case, which also uses only 1 byte.
HTH
Mike
|
|
|
Re: vsize function [message #348 is a reply to message #331] |
Wed, 06 February 2002 07:57 |
hemant shah
Messages: 5 Registered: February 2002
|
Junior Member |
|
|
Thanks Mike.
With larger numbers it can happen, like VSIZE(10000000)=2, that the result is smaller because it will only store the exponent which always uses 1 byte and the number, 1 in this case, which also uses only 1 byte
In other words, 10^7=10,000,000 exponent 1 byte
How did you get the second byte?
|
|
|
Re: vsize function [message #351 is a reply to message #331] |
Wed, 06 February 2002 09:55 |
Mike
Messages: 417 Registered: September 1998
|
Senior Member |
|
|
the second byte stores the 1 (theoreticaly not needed in this case) mulitplying 10^7.
|
|
|
|